Base | Representation |
---|---|
bin | 1100100000111100001… |
… | …00001001001001010101 |
3 | 1112002220111222210100012 |
4 | 12100132010021021111 |
5 | 24021120242211432 |
6 | 525312332330005 |
7 | 43031554213334 |
oct | 6203604111125 |
9 | 1462814883305 |
10 | 430001132117 |
11 | 1563a9479a67 |
12 | 6b406613905 |
13 | 3171a00b81b |
14 | 16b52823d1b |
15 | b2ba697cb2 |
hex | 641e109255 |
430001132117 has 2 divisors, whose sum is σ = 430001132118. Its totient is φ = 430001132116.
The previous prime is 430001132009. The next prime is 430001132137. The reversal of 430001132117 is 711231100034.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 316643669521 + 113357462596 = 562711^2 + 336686^2 .
It is a cyclic number.
It is not a de Polignac number, because 430001132117 - 222 = 429996937813 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 430001132092 and 430001132101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (430001132137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215000566058 + 215000566059.
It is an arithmetic number, because the mean of its divisors is an integer number (215000566059).
Almost surely, 2430001132117 is an apocalyptic number.
It is an amenable number.
430001132117 is a deficient number, since it is larger than the sum of its proper divisors (1).
430001132117 is an equidigital number, since it uses as much as digits as its factorization.
430001132117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
The spelling of 430001132117 in words is "four hundred thirty billion, one million, one hundred thirty-two thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •