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43010000141 is a prime number
BaseRepresentation
bin101000000011100110…
…001000010100001101
311010000102220101110012
4220003212020110031
51201041030001031
631431501323005
73051553653263
oct500346102415
9133012811405
1043010000141
1117271029769
128403b66465
134095858734
142120258433
1511bada3b2b
hexa0398850d

43010000141 has 2 divisors, whose sum is σ = 43010000142. Its totient is φ = 43010000140.

The previous prime is 43010000101. The next prime is 43010000183. The reversal of 43010000141 is 14100001034.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28808272900 + 14201727241 = 169730^2 + 119171^2 .

It is a cyclic number.

It is not a de Polignac number, because 43010000141 - 218 = 43009737997 is a prime.

It is a super-2 number, since 2×430100001412 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43010000101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505000070 + 21505000071.

It is an arithmetic number, because the mean of its divisors is an integer number (21505000071).

Almost surely, 243010000141 is an apocalyptic number.

It is an amenable number.

43010000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43010000141 is an equidigital number, since it uses as much as digits as its factorization.

43010000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 43010000141 its reverse (14100001034), we get a palindrome (57110001175).

The spelling of 43010000141 in words is "forty-three billion, ten million, one hundred forty-one", and thus it is an aban number.