Base | Representation |
---|---|
bin | 10011100011110110000001… |
… | …00111111111011111110000 |
3 | 12122022000011022100211022201 |
4 | 21301323000213333133300 |
5 | 21114211143224230222 |
6 | 231251525400112544 |
7 | 12026406041213644 |
oct | 1161730047773760 |
9 | 178260138324281 |
10 | 43013034211312 |
11 | 127837a8512710 |
12 | 49a826a165754 |
13 | 1b0015b5b7129 |
14 | a89bb04c4c24 |
15 | 4e8d038be427 |
hex | 271ec09ff7f0 |
43013034211312 has 80 divisors (see below), whose sum is σ = 91035370506240. Its totient is φ = 19525265081600.
The previous prime is 43013034211307. The next prime is 43013034211327. The reversal of 43013034211312 is 21311243031034.
It is a super-3 number, since 3×430130342113123 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2084055489 + ... + 2084076127.
It is an arithmetic number, because the mean of its divisors is an integer number (1137942131328).
Almost surely, 243013034211312 is an apocalyptic number.
It is an amenable number.
43013034211312 is an abundant number, since it is smaller than the sum of its proper divisors (48022336294928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43013034211312 is a wasteful number, since it uses less digits than its factorization.
43013034211312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35902 (or 35896 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 43013034211312 its reverse (21311243031034), we get a palindrome (64324277242346).
The spelling of 43013034211312 in words is "forty-three trillion, thirteen billion, thirty-four million, two hundred eleven thousand, three hundred twelve".
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