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43031410055 = 517506251883
BaseRepresentation
bin101000000100110111…
…110011010110000111
311010001221012010022222
4220010313303112013
51201112020110210
631433544242555
73052233643664
oct500467632607
9133057163288
1043031410055
1117282122307
12840b17045b
13409a11381a
14212302ca6b
1511bcbd2655
hexa04df3587

43031410055 has 8 divisors (see below), whose sum is σ = 54675203472. Its totient is φ = 32400120448.

The previous prime is 43031410013. The next prime is 43031410087. The reversal of 43031410055 is 55001413034.

43031410055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 43031410055 - 212 = 43031405959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 253125857 + ... + 253126026.

It is an arithmetic number, because the mean of its divisors is an integer number (6834400434).

Almost surely, 243031410055 is an apocalyptic number.

43031410055 is a deficient number, since it is larger than the sum of its proper divisors (11643793417).

43031410055 is a wasteful number, since it uses less digits than its factorization.

43031410055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 506251905.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 43031410055 its reverse (55001413034), we get a palindrome (98032823089).

The spelling of 43031410055 in words is "forty-three billion, thirty-one million, four hundred ten thousand, fifty-five".

Divisors: 1 5 17 85 506251883 2531259415 8606282011 43031410055