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43043112120101 is a prime number
BaseRepresentation
bin10011100100101110000010…
…11010000110111100100101
312122101212210111020220110112
421302113001122012330211
521120204243200320401
6231313422134102405
712031522305216062
oct1162270132067445
9178355714226415
1043043112120101
1112795532729775
1249b20631aaa05
131b02c42b597b2
14a8b42500dc69
154e99b42873bb
hex2725c1686f25

43043112120101 has 2 divisors, whose sum is σ = 43043112120102. Its totient is φ = 43043112120100.

The previous prime is 43043112120077. The next prime is 43043112120103. The reversal of 43043112120101 is 10102121134034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24380150515876 + 18662961604225 = 4937626^2 + 4320065^2 .

It is a cyclic number.

It is not a de Polignac number, because 43043112120101 - 230 = 43042038378277 is a prime.

Together with 43043112120103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43043112120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21521556060050 + 21521556060051.

It is an arithmetic number, because the mean of its divisors is an integer number (21521556060051).

Almost surely, 243043112120101 is an apocalyptic number.

It is an amenable number.

43043112120101 is a deficient number, since it is larger than the sum of its proper divisors (1).

43043112120101 is an equidigital number, since it uses as much as digits as its factorization.

43043112120101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 43043112120101 its reverse (10102121134034), we get a palindrome (53145233254135).

The spelling of 43043112120101 in words is "forty-three trillion, forty-three billion, one hundred twelve million, one hundred twenty thousand, one hundred one".