Base | Representation |
---|---|
bin | 10011100110011110000100… |
… | …01101110111011011000111 |
3 | 12122121122000222010110021222 |
4 | 21303033002031313123013 |
5 | 21122200431314331101 |
6 | 231401210113430555 |
7 | 12036051563216204 |
oct | 1163170215673307 |
9 | 178548028113258 |
10 | 43103255230151 |
11 | 12808a959724a6 |
12 | 4a01848b6b45b |
13 | 1b0880914278c |
14 | a902cc8b6cab |
15 | 4eb33435801b |
hex | 2733c23776c7 |
43103255230151 has 2 divisors, whose sum is σ = 43103255230152. Its totient is φ = 43103255230150.
The previous prime is 43103255230099. The next prime is 43103255230153. The reversal of 43103255230151 is 15103255230134.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43103255230151 - 222 = 43103251035847 is a prime.
It is a super-2 number, since 2×431032552301512 (a number of 28 digits) contains 22 as substring.
Together with 43103255230153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43103255230153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21551627615075 + 21551627615076.
It is an arithmetic number, because the mean of its divisors is an integer number (21551627615076).
Almost surely, 243103255230151 is an apocalyptic number.
43103255230151 is a deficient number, since it is larger than the sum of its proper divisors (1).
43103255230151 is an equidigital number, since it uses as much as digits as its factorization.
43103255230151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 43103255230151 in words is "forty-three trillion, one hundred three billion, two hundred fifty-five million, two hundred thirty thousand, one hundred fifty-one".
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