431040131 has 2 divisors, whose sum is σ = 431040132. Its totient is φ = 431040130.

The previous prime is 431040013. The next prime is 431040133. The reversal of 431040131 is 131040134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431040131 - 2²² = 426845827 is a prime.

It is a super-2 number, since 2×431040131² = 371591189064994322, which contains 22 as substring.

Together with 431040133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (431040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215520065 + 215520066.

It is an arithmetic number, because the mean of its divisors is an integer number (215520066).

Almost surely, 2^431040131 is an apocalyptic number.

431040131 is a deficient number, since it is larger than the sum of its proper divisors (1).

431040131 is an equidigital number, since it uses as much as digits as its factorization.

431040131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 431040131 is about 20761.5059906549. The cubic root of 431040131 is about 755.3923262495.

Adding to 431040131 its reverse (131040134), we get a palindrome (562080265).

The spelling of 431040131 in words is "four hundred thirty-one million, forty thousand, one hundred thirty-one".