Base | Representation |
---|---|
bin | 111110101111010011011… |
… | …101110101110101010101 |
3 | 120021011110212202101210012 |
4 | 332233103131311311111 |
5 | 1031114221400410031 |
6 | 13100344013010005 |
7 | 623326340306414 |
oct | 76572335656525 |
9 | 16234425671705 |
10 | 4311400013141 |
11 | 14124aaa00531 |
12 | 5976b3183905 |
13 | 253742699240 |
14 | 10c95c51b47b |
15 | 772393c0b2b |
hex | 3ebd3775d55 |
4311400013141 has 8 divisors (see below), whose sum is σ = 4645004466144. Its totient is φ = 3978075317040.
The previous prime is 4311400013117. The next prime is 4311400013183. The reversal of 4311400013141 is 1413100041134.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4311400013141 - 222 = 4311395818837 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4311400013111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69907211 + ... + 69968856.
It is an arithmetic number, because the mean of its divisors is an integer number (580625558268).
Almost surely, 24311400013141 is an apocalyptic number.
It is an amenable number.
4311400013141 is a deficient number, since it is larger than the sum of its proper divisors (333604453003).
4311400013141 is a wasteful number, since it uses less digits than its factorization.
4311400013141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139878451.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 4311400013141 its reverse (1413100041134), we get a palindrome (5724500054275).
The spelling of 4311400013141 in words is "four trillion, three hundred eleven billion, four hundred million, thirteen thousand, one hundred forty-one".
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