Base | Representation |
---|---|
bin | 111110110000000100011… |
… | …010000101011011101100 |
3 | 120021020121002210112201200 |
4 | 332300010122011123230 |
5 | 1031122412101041134 |
6 | 13101001304005500 |
7 | 623355600446646 |
oct | 76600432053354 |
9 | 16236532715650 |
10 | 4312221112044 |
11 | 141289144226a |
12 | 5978a2160890 |
13 | 253843828791 |
14 | 10c9d95b9896 |
15 | 77286514499 |
hex | 3ec046856ec |
4312221112044 has 72 divisors (see below), whose sum is σ = 11425877775312. Its totient is φ = 1369735557120.
The previous prime is 4312221112019. The next prime is 4312221112049. The reversal of 4312221112044 is 4402111222134.
4312221112044 is a `hidden beast` number, since 4 + 312 + 221 + 1 + 120 + 4 + 4 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 4312221111999 and 4312221112017.
It is not an unprimeable number, because it can be changed into a prime (4312221112049) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33908149 + ... + 34035084.
Almost surely, 24312221112044 is an apocalyptic number.
It is an amenable number.
4312221112044 is an abundant number, since it is smaller than the sum of its proper divisors (7113656663268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4312221112044 is a wasteful number, since it uses less digits than its factorization.
4312221112044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67943327 (or 67943322 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 4312221112044 its reverse (4402111222134), we get a palindrome (8714332334178).
The spelling of 4312221112044 in words is "four trillion, three hundred twelve billion, two hundred twenty-one million, one hundred twelve thousand, forty-four".
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