Base | Representation |
---|---|
bin | 101000001010111111… |
… | …101000000001001111 |
3 | 11010100002110112112021 |
4 | 220022333220001033 |
5 | 1201314313432421 |
6 | 31452053551011 |
7 | 3054622001611 |
oct | 501277500117 |
9 | 133302415467 |
10 | 43134124111 |
11 | 173250a7961 |
12 | 8439645467 |
13 | 40b5497780 |
14 | 2132928db1 |
15 | 11c6c21341 |
hex | a0afe804f |
43134124111 has 4 divisors (see below), whose sum is σ = 46452133672. Its totient is φ = 39816114552.
The previous prime is 43134124097. The next prime is 43134124127. The reversal of 43134124111 is 11142143134.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43134124111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43134124141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1659004761 + ... + 1659004786.
It is an arithmetic number, because the mean of its divisors is an integer number (11613033418).
Almost surely, 243134124111 is an apocalyptic number.
43134124111 is a deficient number, since it is larger than the sum of its proper divisors (3318009561).
43134124111 is a wasteful number, since it uses less digits than its factorization.
43134124111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3318009560.
The product of its digits is 1152, while the sum is 25.
Adding to 43134124111 its reverse (11142143134), we get a palindrome (54276267245).
The spelling of 43134124111 in words is "forty-three billion, one hundred thirty-four million, one hundred twenty-four thousand, one hundred eleven".
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