431401114021 has 4 divisors (see below), whose sum is σ = 441433698112. Its totient is φ = 421368529932.

The previous prime is 431401114019. The next prime is 431401114049. The reversal of 431401114021 is 120411104134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 431401114021 - 2¹ = 431401114019 is a prime.

It is a super-4 number, since 4×431401114021⁴ (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 431401113983 and 431401114001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (431401114121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5016291981 + ... + 5016292066.

It is an arithmetic number, because the mean of its divisors is an integer number (110358424528).

Almost surely, 2^431401114021 is an apocalyptic number.

It is an amenable number.

431401114021 is a deficient number, since it is larger than the sum of its proper divisors (10032584091).

431401114021 is a wasteful number, since it uses less digits than its factorization.

431401114021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10032584090.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 431401114021 its reverse (120411104134), we get a palindrome (551812218155).

The spelling of 431401114021 in words is "four hundred thirty-one billion, four hundred one million, one hundred fourteen thousand, twenty-one".