Base | Representation |
---|---|
bin | 10011100111100101000000… |
… | …11100110100110101000000 |
3 | 12122202021100101210120202112 |
4 | 21303302200130310311000 |
5 | 21123311432404311000 |
6 | 231430505400034452 |
7 | 12041600464461362 |
oct | 1163624034646500 |
9 | 178667311716675 |
10 | 43141343432000 |
11 | 12823160747270 |
12 | 4a090b8762a28 |
13 | 1b0c2990c0318 |
14 | a920a31c8d32 |
15 | 4ec3130a1235 |
hex | 273ca0734d40 |
43141343432000 has 224 divisors, whose sum is σ = 121619715819264. Its totient is φ = 15005683968000.
The previous prime is 43141343431999. The next prime is 43141343432017. The reversal of 43141343432000 is 23434314134.
It is a super-2 number, since 2×431413434320002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8633447 + ... + 12681446.
Almost surely, 243141343432000 is an apocalyptic number.
43141343432000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
43141343432000 is an abundant number, since it is smaller than the sum of its proper divisors (78478372387264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43141343432000 is a wasteful number, since it uses less digits than its factorization.
43141343432000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21314954 (or 21314934 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 43141343432000 its reverse (23434314134), we get a palindrome (43164777746134).
The spelling of 43141343432000 in words is "forty-three trillion, one hundred forty-one billion, three hundred forty-three million, four hundred thirty-two thousand".
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