Base | Representation |
---|---|
bin | 101000001011011110… |
… | …100001001011010111 |
3 | 11010100122200222111111 |
4 | 220023132201023113 |
5 | 1201323402110201 |
6 | 31452543315451 |
7 | 3055050561331 |
oct | 501336411327 |
9 | 133318628444 |
10 | 43142222551 |
11 | 1732972938a |
12 | 84402abb87 |
13 | 40b707194c |
14 | 2133a36451 |
15 | 11c77c0b51 |
hex | a0b7a12d7 |
43142222551 has 2 divisors, whose sum is σ = 43142222552. Its totient is φ = 43142222550.
The previous prime is 43142222483. The next prime is 43142222581. The reversal of 43142222551 is 15522224134.
It is a happy number.
43142222551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43142222551 - 223 = 43133833943 is a prime.
It is a super-2 number, since 2×431422225512 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43142222581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571111275 + 21571111276.
It is an arithmetic number, because the mean of its divisors is an integer number (21571111276).
Almost surely, 243142222551 is an apocalyptic number.
43142222551 is a deficient number, since it is larger than the sum of its proper divisors (1).
43142222551 is an equidigital number, since it uses as much as digits as its factorization.
43142222551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19200, while the sum is 31.
Adding to 43142222551 its reverse (15522224134), we get a palindrome (58664446685).
The spelling of 43142222551 in words is "forty-three billion, one hundred forty-two million, two hundred twenty-two thousand, five hundred fifty-one".
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