Base | Representation |
---|---|
bin | 1100100101011011100… |
… | …10011100110001001000 |
3 | 1112100010120020112212120 |
4 | 12102231302130301020 |
5 | 24041040034204000 |
6 | 530351510411240 |
7 | 43145403602631 |
oct | 6225562346110 |
9 | 1470116215776 |
10 | 432412413000 |
11 | 157426596a87 |
12 | 6b97a060b20 |
13 | 31a12747049 |
14 | 16d00b7c888 |
15 | b3ac1eb6a0 |
hex | 64adc9cc48 |
432412413000 has 64 divisors (see below), whose sum is σ = 1349126737920. Its totient is φ = 115309976000.
The previous prime is 432412412989. The next prime is 432412413011. The reversal of 432412413000 is 314214234.
It is an interprime number because it is at equal distance from previous prime (432412412989) and next prime (432412413011).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72065736 + ... + 72071735.
It is an arithmetic number, because the mean of its divisors is an integer number (21080105280).
Almost surely, 2432412413000 is an apocalyptic number.
432412413000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
432412413000 is an abundant number, since it is smaller than the sum of its proper divisors (916714324920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
432412413000 is a wasteful number, since it uses less digits than its factorization.
432412413000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 144137495 (or 144137481 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 432412413000 its reverse (314214234), we get a palindrome (432726627234).
The spelling of 432412413000 in words is "four hundred thirty-two billion, four hundred twelve million, four hundred thirteen thousand".
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