Base | Representation |
---|---|
bin | 1100100110110000000… |
… | …10110001001101110100 |
3 | 1112101221222012110211210 |
4 | 12103120002301031310 |
5 | 24044013030143012 |
6 | 530550113201420 |
7 | 43202102411244 |
oct | 6233002611564 |
9 | 1471858173753 |
10 | 433121334132 |
11 | 15775a779a13 |
12 | 6bb37560270 |
13 | 31ac658abc6 |
14 | 16d6ad99b24 |
15 | b3ee58223c |
hex | 64d80b1374 |
433121334132 has 48 divisors (see below), whose sum is σ = 1030432378752. Its totient is φ = 141546887040.
The previous prime is 433121334101. The next prime is 433121334161. The reversal of 433121334132 is 231433121334.
It is a nude number because it is divisible by every one of its digits.
It is a self number, because there is not a number n which added to its sum of digits gives 433121334132.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 631753 + ... + 1124879.
It is an arithmetic number, because the mean of its divisors is an integer number (21467341224).
Almost surely, 2433121334132 is an apocalyptic number.
It is an amenable number.
433121334132 is an abundant number, since it is smaller than the sum of its proper divisors (597311044620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
433121334132 is a wasteful number, since it uses less digits than its factorization.
433121334132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 494568 (or 494566 counting only the distinct ones).
The product of its digits is 15552, while the sum is 30.
Adding to 433121334132 its reverse (231433121334), we get a palindrome (664554455466).
The spelling of 433121334132 in words is "four hundred thirty-three billion, one hundred twenty-one million, three hundred thirty-four thousand, one hundred thirty-two".
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