Base | Representation |
---|---|
bin | 111111000001110000100… |
… | …000010100001001101001 |
3 | 120100001121210022100111221 |
4 | 333001300200110021221 |
5 | 1031430311411204310 |
6 | 13113422115222041 |
7 | 624630351156304 |
oct | 77016040241151 |
9 | 16301553270457 |
10 | 4331214553705 |
11 | 141a948779096 |
12 | 59b502ba7921 |
13 | 25557c80b060 |
14 | 10d8bbd27b3b |
15 | 779e8c05ada |
hex | 3f070814269 |
4331214553705 has 64 divisors (see below), whose sum is σ = 5697321477120. Its totient is φ = 3141857673216.
The previous prime is 4331214553691. The next prime is 4331214553709. The reversal of 4331214553705 is 5073554121334.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4331214553705 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4331214553709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 463871797 + ... + 463881133.
It is an arithmetic number, because the mean of its divisors is an integer number (89020648080).
Almost surely, 24331214553705 is an apocalyptic number.
It is an amenable number.
4331214553705 is a deficient number, since it is larger than the sum of its proper divisors (1366106923415).
4331214553705 is a wasteful number, since it uses less digits than its factorization.
4331214553705 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10010.
The product of its (nonzero) digits is 756000, while the sum is 43.
The spelling of 4331214553705 in words is "four trillion, three hundred thirty-one billion, two hundred fourteen million, five hundred fifty-three thousand, seven hundred five".
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