Base | Representation |
---|---|
bin | 111111000001110010110… |
… | …100001010111100011000 |
3 | 120100001201111020112200122 |
4 | 333001302310022330120 |
5 | 1031430401322011204 |
6 | 13113430022052412 |
7 | 624631331500121 |
oct | 77016264127430 |
9 | 16301644215618 |
10 | 4331253313304 |
11 | 141a968641815 |
12 | 59b513b7a108 |
13 | 25558785c128 |
14 | 10d8c3137048 |
15 | 779ec3100be |
hex | 3f072d0af18 |
4331253313304 has 64 divisors (see below), whose sum is σ = 8505042517440. Its totient is φ = 2063940341760.
The previous prime is 4331253313259. The next prime is 4331253313349. The reversal of 4331253313304 is 4033133521334.
4331253313304 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (4331253313259) and next prime (4331253313349).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60594674 + ... + 60666110.
It is an arithmetic number, because the mean of its divisors is an integer number (132891289335).
Almost surely, 24331253313304 is an apocalyptic number.
It is an amenable number.
4331253313304 is a deficient number, since it is larger than the sum of its proper divisors (4173789204136).
4331253313304 is a wasteful number, since it uses less digits than its factorization.
4331253313304 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72660 (or 72656 counting only the distinct ones).
The product of its (nonzero) digits is 116640, while the sum is 35.
Adding to 4331253313304 its reverse (4033133521334), we get a palindrome (8364386834638).
The spelling of 4331253313304 in words is "four trillion, three hundred thirty-one billion, two hundred fifty-three million, three hundred thirteen thousand, three hundred four".
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