Base | Representation |
---|---|
bin | 1100100110110010100… |
… | …10100001011100000111 |
3 | 1112102000102112122201101 |
4 | 12103121102201130013 |
5 | 24044033403203111 |
6 | 530552141240531 |
7 | 43202445205303 |
oct | 6233122413407 |
9 | 1472012478641 |
10 | 433142241031 |
11 | 157770559645 |
12 | 6bb42563147 |
13 | 31aca9cb056 |
14 | 16d6da7cd03 |
15 | b401311bc1 |
hex | 64d94a1707 |
433142241031 has 2 divisors, whose sum is σ = 433142241032. Its totient is φ = 433142241030.
The previous prime is 433142241019. The next prime is 433142241043. The reversal of 433142241031 is 130142241334.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (433142241019) and next prime (433142241043).
It is a cyclic number.
It is not a de Polignac number, because 433142241031 - 221 = 433140143879 is a prime.
It is a super-2 number, since 2×4331422410312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (433142242031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216571120515 + 216571120516.
It is an arithmetic number, because the mean of its divisors is an integer number (216571120516).
Almost surely, 2433142241031 is an apocalyptic number.
433142241031 is a deficient number, since it is larger than the sum of its proper divisors (1).
433142241031 is an equidigital number, since it uses as much as digits as its factorization.
433142241031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 433142241031 its reverse (130142241334), we get a palindrome (563284482365).
The spelling of 433142241031 in words is "four hundred thirty-three billion, one hundred forty-two million, two hundred forty-one thousand, thirty-one".
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