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433144230103 = 131712715432509
BaseRepresentation
bin1100100110110010110…
…10000111000011010111
31112102000120021201012201
412103121122013003113
524044034410330403
6530552252025331
743202501131324
oct6233132070327
91472016251181
10433144230103
11157771698002
126bb43162247
1331acb246510
1416d70039b4b
15b4015a621d
hex64d96870d7

433144230103 has 16 divisors (see below), whose sum is σ = 497791042560. Its totient is φ = 373343233536.

The previous prime is 433144230091. The next prime is 433144230121. The reversal of 433144230103 is 301032441334.

It is not a de Polignac number, because 433144230103 - 233 = 424554295511 is a prime.

It is a super-2 number, since 2×4331442301032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (433144230143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7688188 + ... + 7744321.

It is an arithmetic number, because the mean of its divisors is an integer number (31111940160).

Almost surely, 2433144230103 is an apocalyptic number.

433144230103 is a deficient number, since it is larger than the sum of its proper divisors (64646812457).

433144230103 is a wasteful number, since it uses less digits than its factorization.

433144230103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15432666.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 433144230103 its reverse (301032441334), we get a palindrome (734176671437).

The spelling of 433144230103 in words is "four hundred thirty-three billion, one hundred forty-four million, two hundred thirty thousand, one hundred three".

Divisors: 1 13 17 127 221 1651 2159 28067 15432509 200622617 262352653 1959928643 3410584489 25479072359 33318786931 433144230103