Base | Representation |
---|---|
bin | 111111000100101001000… |
… | …100011001011000000000 |
3 | 120100100121120212010202222 |
4 | 333010221010121120000 |
5 | 1032003132110120112 |
6 | 13115053251230212 |
7 | 625100160536030 |
oct | 77045104313000 |
9 | 16310546763688 |
10 | 4334311020032 |
11 | 1421197637074 |
12 | 5a0027ba8368 |
13 | 255954199856 |
14 | 10dad32818c0 |
15 | 77b2a9a2372 |
hex | 3f129119600 |
4334311020032 has 80 divisors (see below), whose sum is σ = 9925847205120. Its totient is φ = 1852208130048.
The previous prime is 4334311020029. The next prime is 4334311020043. The reversal of 4334311020032 is 2300201134334.
It is a junction number, because it is equal to n+sod(n) for n = 4334311019983 and 4334311020010.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 498932 + ... + 2986227.
It is an arithmetic number, because the mean of its divisors is an integer number (124073090064).
Almost surely, 24334311020032 is an apocalyptic number.
It is an amenable number.
4334311020032 is an abundant number, since it is smaller than the sum of its proper divisors (5591536185088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4334311020032 is an equidigital number, since it uses as much as digits as its factorization.
4334311020032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3485531 (or 3485515 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 4334311020032 its reverse (2300201134334), we get a palindrome (6634512154366).
The spelling of 4334311020032 in words is "four trillion, three hundred thirty-four billion, three hundred eleven million, twenty thousand, thirty-two".
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