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43402013 is a prime number
BaseRepresentation
bin1010010110010…
…0001100011101
310000200001100222
42211210030131
542102331023
64150131125
71034624324
oct245441435
9100601328
1043402013
1122554636
1212650aa5
138cb8185
145a9b0bb
153c24cc8
hex296431d

43402013 has 2 divisors, whose sum is σ = 43402014. Its totient is φ = 43402012.

The previous prime is 43402001. The next prime is 43402019. The reversal of 43402013 is 31020434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38962564 + 4439449 = 6242^2 + 2107^2 .

It is a cyclic number.

It is not a de Polignac number, because 43402013 - 26 = 43401949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43401982 and 43402000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43402019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21701006 + 21701007.

It is an arithmetic number, because the mean of its divisors is an integer number (21701007).

Almost surely, 243402013 is an apocalyptic number.

It is an amenable number.

43402013 is a deficient number, since it is larger than the sum of its proper divisors (1).

43402013 is an equidigital number, since it uses as much as digits as its factorization.

43402013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 43402013 is about 6588.0204158761. The cubic root of 43402013 is about 351.4282130735.

Adding to 43402013 its reverse (31020434), we get a palindrome (74422447).

The spelling of 43402013 in words is "forty-three million, four hundred two thousand, thirteen".