43403111021 has 2 divisors, whose sum is σ = 43403111022. Its totient is φ = 43403111020.

The previous prime is 43403110979. The next prime is 43403111023. The reversal of 43403111021 is 12011130434.

43403111021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38075716900 + 5327394121 = 195130^2 + 72989^2 .

It is a cyclic number.

It is not a de Polignac number, because 43403111021 - 2³⁰ = 42329369197 is a prime.

Together with 43403111023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43403110984 and 43403111002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43403111023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21701555510 + 21701555511.

It is an arithmetic number, because the mean of its divisors is an integer number (21701555511).

Almost surely, 2^43403111021 is an apocalyptic number.

It is an amenable number.

43403111021 is a deficient number, since it is larger than the sum of its proper divisors (1).

43403111021 is an equidigital number, since it uses as much as digits as its factorization.

43403111021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 43403111021 its reverse (12011130434), we get a palindrome (55414241455).

The spelling of 43403111021 in words is "forty-three billion, four hundred three million, one hundred eleven thousand, twenty-one".