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43404131 is a prime number
BaseRepresentation
bin1010010110010…
…0101101100011
310000200011021102
42211210231203
542102413011
64150145015
71034633441
oct245445543
9100604242
1043404131
1122556191
121265216b
138cb9124
145a9bb91
153c2573b
hex2964b63

43404131 has 2 divisors, whose sum is σ = 43404132. Its totient is φ = 43404130.

The previous prime is 43404079. The next prime is 43404133. The reversal of 43404131 is 13140434.

It is a happy number.

43404131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43404131 is a prime.

It is a super-2 number, since 2×434041312 = 3767837175730322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 43404133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (43404133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21702065 + 21702066.

It is an arithmetic number, because the mean of its divisors is an integer number (21702066).

Almost surely, 243404131 is an apocalyptic number.

43404131 is a deficient number, since it is larger than the sum of its proper divisors (1).

43404131 is an equidigital number, since it uses as much as digits as its factorization.

43404131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 43404131 is about 6588.1811602293. The cubic root of 43404131 is about 351.4339294969.

Adding to 43404131 its reverse (13140434), we get a palindrome (56544565).

The spelling of 43404131 in words is "forty-three million, four hundred four thousand, one hundred thirty-one".