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434100000221 is a prime number
BaseRepresentation
bin1100101000100100110…
…00000101010111011101
31112111111011201212022222
412110102120011113131
524103014100001341
6531231153315125
743235255056166
oct6242230052735
91474434655288
10434100000221
11158112151268
127016b265aa5
1331c21268774
1417020d5276d
15b45a44c44b
hex65126055dd

434100000221 has 2 divisors, whose sum is σ = 434100000222. Its totient is φ = 434100000220.

The previous prime is 434100000211. The next prime is 434100000223. The reversal of 434100000221 is 122000001434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 416909119225 + 17190880996 = 645685^2 + 131114^2 .

It is a cyclic number.

It is not a de Polignac number, because 434100000221 - 218 = 434099738077 is a prime.

Together with 434100000223, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 434100000221.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434100000223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217050000110 + 217050000111.

It is an arithmetic number, because the mean of its divisors is an integer number (217050000111).

Almost surely, 2434100000221 is an apocalyptic number.

It is an amenable number.

434100000221 is a deficient number, since it is larger than the sum of its proper divisors (1).

434100000221 is an equidigital number, since it uses as much as digits as its factorization.

434100000221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 434100000221 its reverse (122000001434), we get a palindrome (556100001655).

The spelling of 434100000221 in words is "four hundred thirty-four billion, one hundred million, two hundred twenty-one", and thus it is an aban number.