4341123000145 has 4 divisors (see below), whose sum is σ = 5209347600180. Its totient is φ = 3472898400112.

The previous prime is 4341123000121. The next prime is 4341123000217. The reversal of 4341123000145 is 5410003211434.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 886286679184 + 3454836320961 = 941428^2 + 1858719^2 .

It is a cyclic number.

It is not a de Polignac number, because 4341123000145 - 2¹¹ = 4341122998097 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434112300010 + ... + 434112300019.

It is an arithmetic number, because the mean of its divisors is an integer number (1302336900045).

Almost surely, 2^{4341123000145} is an apocalyptic number.

It is an amenable number.

4341123000145 is a deficient number, since it is larger than the sum of its proper divisors (868224600035).

4341123000145 is an equidigital number, since it uses as much as digits as its factorization.

4341123000145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 868224600034.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 4341123000145 its reverse (5410003211434), we get a palindrome (9751126211579).

The spelling of 4341123000145 in words is "four trillion, three hundred forty-one billion, one hundred twenty-three million, one hundred forty-five", and thus it is an aban number.