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434121011 is a prime number
BaseRepresentation
bin11001111000000…
…010100100110011
31010020212122001222
4121320002210303
51342113333021
6111024415255
713520652632
oct3170024463
91106778058
10434121011
112030605a5
1210147752b
136bc2a24c
1441927519
15281a36ab
hex19e02933

434121011 has 2 divisors, whose sum is σ = 434121012. Its totient is φ = 434121010.

The previous prime is 434120983. The next prime is 434121029. The reversal of 434121011 is 110121434.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-434121011 is a prime.

It is a super-2 number, since 2×4341210112 = 376922104383324242, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (434121071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217060505 + 217060506.

It is an arithmetic number, because the mean of its divisors is an integer number (217060506).

Almost surely, 2434121011 is an apocalyptic number.

434121011 is a deficient number, since it is larger than the sum of its proper divisors (1).

434121011 is an equidigital number, since it uses as much as digits as its factorization.

434121011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 434121011 is about 20835.5708105154. The cubic root of 434121011 is about 757.1877895879.

Adding to 434121011 its reverse (110121434), we get a palindrome (544242445).

It can be divided in two parts, 4341 and 21011, that added together give a palindrome (25352).

The spelling of 434121011 in words is "four hundred thirty-four million, one hundred twenty-one thousand, eleven".