Base | Representation |
---|---|
bin | 110001010110101001011111… |
… | …0101001101111100110010000 |
3 | 2002221002120222201111201220212 |
4 | 1202231102332221233212100 |
5 | 423400120422113240100 |
6 | 4135144324503223252 |
7 | 160304141556124601 |
oct | 14255227651574620 |
9 | 2087076881451825 |
10 | 434121313024400 |
11 | 1163628a6757071 |
12 | 40833751447b28 |
13 | 158306059b80b1 |
14 | 792b8257cbda8 |
15 | 352c75927c635 |
hex | 18ad4bea6f990 |
434121313024400 has 120 divisors (see below), whose sum is σ = 1049538318760320. Its totient is φ = 172556350686720.
The previous prime is 434121313024391. The next prime is 434121313024417. The reversal of 434121313024400 is 4420313121434.
It is a super-2 number, since 2×4341213130244002 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 421264169 + ... + 422293431.
It is an arithmetic number, because the mean of its divisors is an integer number (8746152656336).
Almost surely, 2434121313024400 is an apocalyptic number.
434121313024400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 434121313024400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (524769159380160).
434121313024400 is an abundant number, since it is smaller than the sum of its proper divisors (615417005735920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
434121313024400 is a wasteful number, since it uses less digits than its factorization.
434121313024400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1035913 (or 1035902 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 434121313024400 its reverse (4420313121434), we get a palindrome (438541626145834).
The spelling of 434121313024400 in words is "four hundred thirty-four trillion, one hundred twenty-one billion, three hundred thirteen million, twenty-four thousand, four hundred".
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