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43436121581 is a prime number
BaseRepresentation
bin101000011100111111…
…101001110111101101
311011010010201121011202
4220130333221313231
51202424121342311
631542042455245
73065246640656
oct503477516755
9134103647152
1043436121581
111746a616046
128502804525
134132c147b8
142160a9c52d
1511e34c6e3b
hexa1cfe9ded

43436121581 has 2 divisors, whose sum is σ = 43436121582. Its totient is φ = 43436121580.

The previous prime is 43436121569. The next prime is 43436121583. The reversal of 43436121581 is 18512163434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36574650025 + 6861471556 = 191245^2 + 82834^2 .

It is a cyclic number.

It is not a de Polignac number, because 43436121581 - 210 = 43436120557 is a prime.

It is a super-2 number, since 2×434361215812 (a number of 22 digits) contains 22 as substring.

Together with 43436121583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43436121583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21718060790 + 21718060791.

It is an arithmetic number, because the mean of its divisors is an integer number (21718060791).

Almost surely, 243436121581 is an apocalyptic number.

It is an amenable number.

43436121581 is a deficient number, since it is larger than the sum of its proper divisors (1).

43436121581 is an equidigital number, since it uses as much as digits as its factorization.

43436121581 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 38.

The spelling of 43436121581 in words is "forty-three billion, four hundred thirty-six million, one hundred twenty-one thousand, five hundred eighty-one".