Base | Representation |
---|---|
bin | 111111010011011001001… |
… | …001011100001001110011 |
3 | 120101212111102202102022020 |
4 | 333103121021130021303 |
5 | 1032233101402042120 |
6 | 13130233100242523 |
7 | 626200526122311 |
oct | 77233111341163 |
9 | 16355442672266 |
10 | 4350150034035 |
11 | 1427985316793 |
12 | 5a3108540443 |
13 | 2572a97a85a0 |
14 | 110796aa90b1 |
15 | 78256298640 |
hex | 3f4d925c273 |
4350150034035 has 32 divisors (see below), whose sum is σ = 7498912830528. Its totient is φ = 2140678126080.
The previous prime is 4350150033997. The next prime is 4350150034051. The reversal of 4350150034035 is 5304300510534.
It is not a de Polignac number, because 4350150034035 - 211 = 4350150031987 is a prime.
It is a super-2 number, since 2×43501500340352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4350150033987 and 4350150034005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4417336 + ... + 5311605.
It is an arithmetic number, because the mean of its divisors is an integer number (234341025954).
Almost surely, 24350150034035 is an apocalyptic number.
4350150034035 is a deficient number, since it is larger than the sum of its proper divisors (3148762796493).
4350150034035 is a wasteful number, since it uses less digits than its factorization.
4350150034035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9731255.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 4350150034035 its reverse (5304300510534), we get a palindrome (9654450544569).
The spelling of 4350150034035 in words is "four trillion, three hundred fifty billion, one hundred fifty million, thirty-four thousand, thirty-five".
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