Base | Representation |
---|---|
bin | 1000001101000000… |
… | …10111000000011101 |
3 | 102100221010010212111 |
4 | 10012200113000131 |
5 | 33004423112222 |
6 | 2005003234021 |
7 | 214065226603 |
oct | 40640270035 |
9 | 12327103774 |
10 | 4404113437 |
11 | 1960009679 |
12 | a2ab18911 |
13 | 5525733a9 |
14 | 2daca9873 |
15 | 1ab99c777 |
hex | 10681701d |
4404113437 has 2 divisors, whose sum is σ = 4404113438. Its totient is φ = 4404113436.
The previous prime is 4404113369. The next prime is 4404113447. The reversal of 4404113437 is 7343114044.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4374367321 + 29746116 = 66139^2 + 5454^2 .
It is a cyclic number.
It is not a de Polignac number, because 4404113437 - 215 = 4404080669 is a prime.
It is a super-3 number, since 3×44041134373 (a number of 30 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4404113399 and 4404113408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4404113447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202056718 + 2202056719.
It is an arithmetic number, because the mean of its divisors is an integer number (2202056719).
Almost surely, 24404113437 is an apocalyptic number.
It is an amenable number.
4404113437 is a deficient number, since it is larger than the sum of its proper divisors (1).
4404113437 is an equidigital number, since it uses as much as digits as its factorization.
4404113437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
The square root of 4404113437 is about 66363.4947618041. The cubic root of 4404113437 is about 1639.1530225242.
The spelling of 4404113437 in words is "four billion, four hundred four million, one hundred thirteen thousand, four hundred thirty-seven".
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