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4411991413471 is a prime number
BaseRepresentation
bin100000000110011111100…
…1011100101001011011111
3120121210010021012222202211
41000030333023211023133
51034241224300212341
613214501343501251
7633520155146215
oct100147713451337
916553107188684
104411991413471
11145112a150434
125b30a6bb7827
132600838831b5
14113781d26cb5
1579b754ca181
hex4033f2e52df

4411991413471 has 2 divisors, whose sum is σ = 4411991413472. Its totient is φ = 4411991413470.

The previous prime is 4411991413469. The next prime is 4411991413483. The reversal of 4411991413471 is 1743141991144.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4411991413471 - 21 = 4411991413469 is a prime.

It is a super-3 number, since 3×44119914134713 (a number of 39 digits) contains 333 as substring.

Together with 4411991413469, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4411991410471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2205995706735 + 2205995706736.

It is an arithmetic number, because the mean of its divisors is an integer number (2205995706736).

Almost surely, 24411991413471 is an apocalyptic number.

4411991413471 is a deficient number, since it is larger than the sum of its proper divisors (1).

4411991413471 is an equidigital number, since it uses as much as digits as its factorization.

4411991413471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 435456, while the sum is 49.

The spelling of 4411991413471 in words is "four trillion, four hundred eleven billion, nine hundred ninety-one million, four hundred thirteen thousand, four hundred seventy-one".