4431211101131 has 4 divisors (see below), whose sum is σ = 4431675063264. Its totient is φ = 4430747139000.

The previous prime is 4431211101101. The next prime is 4431211101143. The reversal of 4431211101131 is 1311011121344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4431211101131 - 2¹⁴ = 4431211084747 is a prime.

It is a super-2 number, since 2×4431211101131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4431211101097 and 4431211101106.

It is not an unprimeable number, because it can be changed into a prime (4431211101101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231966740 + ... + 231985841.

It is an arithmetic number, because the mean of its divisors is an integer number (1107918765816).

Almost surely, 2^{4431211101131} is an apocalyptic number.

4431211101131 is a deficient number, since it is larger than the sum of its proper divisors (463962133).

4431211101131 is an equidigital number, since it uses as much as digits as its factorization.

4431211101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 463962132.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 4431211101131 its reverse (1311011121344), we get a palindrome (5742222222475).

The spelling of 4431211101131 in words is "four trillion, four hundred thirty-one billion, two hundred eleven million, one hundred one thousand, one hundred thirty-one".