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44331329957 is a prime number
BaseRepresentation
bin101001010010010110…
…100110100110100101
311020102112012220012112
4221102112212212211
51211242310024312
632210542130405
73126400041635
oct512226464645
9136375186175
1044331329957
1117889975382
128712580a05
1342465211b5
14220792c6c5
151246da8d22
hexa525a69a5

44331329957 has 2 divisors, whose sum is σ = 44331329958. Its totient is φ = 44331329956.

The previous prime is 44331329839. The next prime is 44331330007. The reversal of 44331329957 is 75992313344.

It is an a-pointer prime, because the next prime (44331330007) can be obtained adding 44331329957 to its sum of digits (50).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42798920641 + 1532409316 = 206879^2 + 39146^2 .

It is a cyclic number.

It is not a de Polignac number, because 44331329957 - 232 = 40036362661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44331329057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22165664978 + 22165664979.

It is an arithmetic number, because the mean of its divisors is an integer number (22165664979).

Almost surely, 244331329957 is an apocalyptic number.

It is an amenable number.

44331329957 is a deficient number, since it is larger than the sum of its proper divisors (1).

44331329957 is an equidigital number, since it uses as much as digits as its factorization.

44331329957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2449440, while the sum is 50.

The spelling of 44331329957 in words is "forty-four billion, three hundred thirty-one million, three hundred twenty-nine thousand, nine hundred fifty-seven".