44405214142133 has 4 divisors (see below), whose sum is σ = 47820999845388. Its totient is φ = 40989428438880.

The previous prime is 44405214142073. The next prime is 44405214142183. The reversal of 44405214142133 is 33124141250444.

44405214142133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9019348387729 + 35385865754404 = 3003223^2 + 5948602^2 .

It is a cyclic number.

It is not a de Polignac number, because 44405214142133 - 2¹⁰ = 44405214141109 is a prime.

It is a super-3 number, since 3×44405214142133³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44405214142183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1707892851608 + ... + 1707892851633.

It is an arithmetic number, because the mean of its divisors is an integer number (11955249961347).

Almost surely, 2^{44405214142133} is an apocalyptic number.

It is an amenable number.

44405214142133 is a deficient number, since it is larger than the sum of its proper divisors (3415785703255).

44405214142133 is a wasteful number, since it uses less digits than its factorization.

44405214142133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3415785703254.

The product of its (nonzero) digits is 184320, while the sum is 38.

Adding to 44405214142133 its reverse (33124141250444), we get a palindrome (77529355392577).

The spelling of 44405214142133 in words is "forty-four trillion, four hundred five billion, two hundred fourteen million, one hundred forty-two thousand, one hundred thirty-three".