444122440114341 has 4 divisors (see below), whose sum is σ = 592163253485792. Its totient is φ = 296081626742892.

The previous prime is 444122440114333. The next prime is 444122440114357. The reversal of 444122440114341 is 143411044221444.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 444122440114341 - 2³ = 444122440114333 is a prime.

It is a super-3 number, since 3×444122440114341³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 444122440114341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (444122440114321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74020406685721 + ... + 74020406685726.

It is an arithmetic number, because the mean of its divisors is an integer number (148040813371448).

Almost surely, 2^{444122440114341} is an apocalyptic number.

It is an amenable number.

444122440114341 is a deficient number, since it is larger than the sum of its proper divisors (148040813371451).

444122440114341 is a wasteful number, since it uses less digits than its factorization.

444122440114341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 148040813371450.

The product of its (nonzero) digits is 196608, while the sum is 39.

Adding to 444122440114341 its reverse (143411044221444), we get a palindrome (587533484335785).

The spelling of 444122440114341 in words is "four hundred forty-four trillion, one hundred twenty-two billion, four hundred forty million, one hundred fourteen thousand, three hundred forty-one".