Base | Representation |
---|---|
bin | 1100111011110110110… |
… | …10010100110011101111 |
3 | 1120111012122002112202011 |
4 | 12131323122110303233 |
5 | 24240214221130111 |
6 | 540102315342051 |
7 | 44052636525520 |
oct | 6357332246357 |
9 | 1514178075664 |
10 | 444452130031 |
11 | 161544705648 |
12 | 7217a151927 |
13 | 32bb0ba6670 |
14 | 17723b78847 |
15 | b8641b5021 |
hex | 677b694cef |
444452130031 has 32 divisors (see below), whose sum is σ = 579288786048. Its totient is φ = 330915594240.
The previous prime is 444452130029. The next prime is 444452130043. The reversal of 444452130031 is 130031254444.
It is not a de Polignac number, because 444452130031 - 21 = 444452130029 is a prime.
It is a super-2 number, since 2×4444521300312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 444452129975 and 444452130002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (444452139031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11417541 + ... + 11456401.
It is an arithmetic number, because the mean of its divisors is an integer number (18102774564).
Almost surely, 2444452130031 is an apocalyptic number.
444452130031 is a deficient number, since it is larger than the sum of its proper divisors (134836656017).
444452130031 is a wasteful number, since it uses less digits than its factorization.
444452130031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46291.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 444452130031 its reverse (130031254444), we get a palindrome (574483384475).
The spelling of 444452130031 in words is "four hundred forty-four billion, four hundred fifty-two million, one hundred thirty thousand, thirty-one".
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