Base | Representation |
---|---|
bin | 10100011101101111100001… |
… | …10111111010111011100111 |
3 | 12220100012002120120020201212 |
4 | 22032313300313322323213 |
5 | 21344304420332120320 |
6 | 235413453503342035 |
7 | 12323213521462532 |
oct | 1216676067727347 |
9 | 186305076506655 |
10 | 45002413551335 |
11 | 1338046426a459 |
12 | 50699292b191b |
13 | 1c1592b6b07c6 |
14 | b181b260ba19 |
15 | 53093928e9c5 |
hex | 28edf0dfaee7 |
45002413551335 has 16 divisors (see below), whose sum is σ = 56634018393600. Its totient is φ = 34263581093280.
The previous prime is 45002413551299. The next prime is 45002413551371. The reversal of 45002413551335 is 53315531420054.
It is an interprime number because it is at equal distance from previous prime (45002413551299) and next prime (45002413551371).
It is not a de Polignac number, because 45002413551335 - 212 = 45002413547239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 45002413551292 and 45002413551301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 983206601 + ... + 983252370.
It is an arithmetic number, because the mean of its divisors is an integer number (3539626149600).
Almost surely, 245002413551335 is an apocalyptic number.
45002413551335 is a deficient number, since it is larger than the sum of its proper divisors (11631604842265).
45002413551335 is a wasteful number, since it uses less digits than its factorization.
45002413551335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1966459198.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 45002413551335 its reverse (53315531420054), we get a palindrome (98317944971389).
The spelling of 45002413551335 in words is "forty-five trillion, two billion, four hundred thirteen million, five hundred fifty-one thousand, three hundred thirty-five".
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