Base | Representation |
---|---|
bin | 101101000010000010… |
… | …001001101011110111 |
3 | 11121210202202112010210 |
4 | 231002002021223313 |
5 | 1243011220003341 |
6 | 34113545520503 |
7 | 3331135321062 |
oct | 550202115367 |
9 | 147722675123 |
10 | 48352500471 |
11 | 195627a92a0 |
12 | 94551a3133 |
13 | 4737645a32 |
14 | 24a99d38d9 |
15 | 13cee11c16 |
hex | b42089af7 |
48352500471 has 8 divisors (see below), whose sum is σ = 70330909824. Its totient is φ = 29304545720.
The previous prime is 48352500419. The next prime is 48352500473. The reversal of 48352500471 is 17400525384.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 48352500471 - 215 = 48352467703 is a prime.
It is a super-3 number, since 3×483525004713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48352500473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 732613611 + ... + 732613676.
It is an arithmetic number, because the mean of its divisors is an integer number (8791363728).
Almost surely, 248352500471 is an apocalyptic number.
48352500471 is a deficient number, since it is larger than the sum of its proper divisors (21978409353).
48352500471 is a wasteful number, since it uses less digits than its factorization.
48352500471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1465227301.
The product of its (nonzero) digits is 134400, while the sum is 39.
The spelling of 48352500471 in words is "forty-eight billion, three hundred fifty-two million, five hundred thousand, four hundred seventy-one".
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