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48362377333 is a prime number
BaseRepresentation
bin101101000010100111…
…110101000001110101
311121211110100022122111
4231002213311001311
51243021232033313
634114541331021
73331315265434
oct550247650165
9147743308574
1048362377333
1119568334996
129458566a71
1347396c352a
1424ab04511b
1513d0c1343d
hexb429f5075

48362377333 has 2 divisors, whose sum is σ = 48362377334. Its totient is φ = 48362377332.

The previous prime is 48362377331. The next prime is 48362377361. The reversal of 48362377333 is 33377326384.

It is a happy number.

48362377333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48339738769 + 22638564 = 219863^2 + 4758^2 .

It is a cyclic number.

It is not a de Polignac number, because 48362377333 - 21 = 48362377331 is a prime.

Together with 48362377331, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48362377331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24181188666 + 24181188667.

It is an arithmetic number, because the mean of its divisors is an integer number (24181188667).

Almost surely, 248362377333 is an apocalyptic number.

It is an amenable number.

48362377333 is a deficient number, since it is larger than the sum of its proper divisors (1).

48362377333 is an equidigital number, since it uses as much as digits as its factorization.

48362377333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4572288, while the sum is 49.

The spelling of 48362377333 in words is "forty-eight billion, three hundred sixty-two million, three hundred seventy-seven thousand, three hundred thirty-three".