Base | Representation |
---|---|
bin | 1001000000111100… |
… | …00010001001101101 |
3 | 110111021202210212012 |
4 | 10200132002021231 |
5 | 34402431230331 |
6 | 2120123451005 |
7 | 230634603413 |
oct | 44036021155 |
9 | 13437683765 |
10 | 4839711341 |
11 | 2063988843 |
12 | b30986a65 |
13 | 5c189992a |
14 | 33ca992b3 |
15 | 1d4d4382b |
hex | 12078226d |
4839711341 has 2 divisors, whose sum is σ = 4839711342. Its totient is φ = 4839711340.
The previous prime is 4839711287. The next prime is 4839711343. The reversal of 4839711341 is 1431179384.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3085358116 + 1754353225 = 55546^2 + 41885^2 .
It is a cyclic number.
It is not a de Polignac number, because 4839711341 - 26 = 4839711277 is a prime.
Together with 4839711343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4839711343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2419855670 + 2419855671.
It is an arithmetic number, because the mean of its divisors is an integer number (2419855671).
Almost surely, 24839711341 is an apocalyptic number.
It is an amenable number.
4839711341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4839711341 is an equidigital number, since it uses as much as digits as its factorization.
4839711341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72576, while the sum is 41.
The square root of 4839711341 is about 69568.0339020732. The cubic root of 4839711341 is about 1691.5044830137.
The spelling of 4839711341 in words is "four billion, eight hundred thirty-nine million, seven hundred eleven thousand, three hundred forty-one".
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