Base | Representation |
---|---|
bin | 110111001001010010010100… |
… | …1000011111010011011111111 |
3 | 2100121110102021200201211000012 |
4 | 1232102210221003322123333 |
5 | 1002034221232030244444 |
6 | 4435350045150053435 |
7 | 204112346635442156 |
oct | 15622445103723377 |
9 | 2317412250654005 |
10 | 485061410399999 |
11 | 130612430711794 |
12 | 464a0198aaa27b |
13 | 17a87130181804 |
14 | 87ad15189659d |
15 | 3b12861737b9e |
hex | 1b929290fa6ff |
485061410399999 has 8 divisors (see below), whose sum is σ = 485622488350080. Its totient is φ = 484500476829600.
The previous prime is 485061410399963. The next prime is 485061410400001. The reversal of 485061410399999 is 999993014160584.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-485061410399999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (485061410399399) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29371064 + ... + 42811005.
It is an arithmetic number, because the mean of its divisors is an integer number (60702811043760).
Almost surely, 2485061410399999 is an apocalyptic number.
485061410399999 is a deficient number, since it is larger than the sum of its proper divisors (561077950081).
485061410399999 is an equidigital number, since it uses as much as digits as its factorization.
485061410399999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72189841.
The product of its (nonzero) digits is 680244480, while the sum is 77.
The spelling of 485061410399999 in words is "four hundred eighty-five trillion, sixty-one billion, four hundred ten million, three hundred ninety-nine thousand, nine hundred ninety-nine".
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