Base | Representation |
---|---|
bin | 101101100100010101… |
… | …010001110011100101 |
3 | 11200021212112212112000 |
4 | 231210111101303211 |
5 | 1300201023033223 |
6 | 34251023315513 |
7 | 3351323424564 |
oct | 554425216345 |
9 | 150255485460 |
10 | 48927939813 |
11 | 198286013a5 |
12 | 9595a4bb99 |
13 | 47c992239c |
14 | 25221c5bdb |
15 | 14156cc543 |
hex | b64551ce5 |
48927939813 has 64 divisors (see below), whose sum is σ = 80193792000. Its totient is φ = 29344664448.
The previous prime is 48927939811. The next prime is 48927939821. The reversal of 48927939813 is 31893972984.
48927939813 is a `hidden beast` number, since 489 + 2 + 79 + 3 + 9 + 81 + 3 = 666.
48927939813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 48927939813 - 21 = 48927939811 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48927939811) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1625145 + ... + 1654977.
It is an arithmetic number, because the mean of its divisors is an integer number (1253028000).
Almost surely, 248927939813 is an apocalyptic number.
It is an amenable number.
48927939813 is a deficient number, since it is larger than the sum of its proper divisors (31265852187).
48927939813 is a wasteful number, since it uses less digits than its factorization.
48927939813 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30023 (or 30017 counting only the distinct ones).
The product of its digits is 23514624, while the sum is 63.
The spelling of 48927939813 in words is "forty-eight billion, nine hundred twenty-seven million, nine hundred thirty-nine thousand, eight hundred thirteen".
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