Base | Representation |
---|---|
bin | 1001001001011111… |
… | …00000001001000101 |
3 | 110200021122221111221 |
4 | 10210233200021011 |
5 | 40024304240433 |
6 | 2131204200341 |
7 | 232465130650 |
oct | 44457401105 |
9 | 13607587457 |
10 | 4911399493 |
11 | 20a03a2150 |
12 | b509990b1 |
13 | 6036a9960 |
14 | 3483da897 |
15 | 1db2a472d |
hex | 124be0245 |
4911399493 has 16 divisors (see below), whose sum is σ = 6594327936. Its totient is φ = 3532674240.
The previous prime is 4911399463. The next prime is 4911399497. The reversal of 4911399493 is 3949931194.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 4911399493 - 217 = 4911268421 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4911399493.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4911399497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2452246 + ... + 2454247.
It is an arithmetic number, because the mean of its divisors is an integer number (412145496).
Almost surely, 24911399493 is an apocalyptic number.
It is an amenable number.
4911399493 is a deficient number, since it is larger than the sum of its proper divisors (1682928443).
4911399493 is a wasteful number, since it uses less digits than its factorization.
4911399493 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4906524.
The product of its digits is 944784, while the sum is 52.
The square root of 4911399493 is about 70081.3776477032. The cubic root of 4911399493 is about 1699.8153770669.
It can be divided in two parts, 4911 and 399493, that added together give a palindrome (404404).
The spelling of 4911399493 in words is "four billion, nine hundred eleven million, three hundred ninety-nine thousand, four hundred ninety-three".
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