Base | Representation |
---|---|
bin | 1001001001110010… |
… | …11011001000111101 |
3 | 110200110120002100111 |
4 | 10210321123020331 |
5 | 40030441003240 |
6 | 2131340030021 |
7 | 232526212624 |
oct | 44471331075 |
9 | 13613502314 |
10 | 4914000445 |
11 | 20a19092a2 |
12 | b51832311 |
13 | 6040aa793 |
14 | 3488b66bb |
15 | 1db61a1ea |
hex | 124e5b23d |
4914000445 has 4 divisors (see below), whose sum is σ = 5896800540. Its totient is φ = 3931200352.
The previous prime is 4914000431. The next prime is 4914000479. The reversal of 4914000445 is 5440004194.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5440004194 = 2 ⋅2720002097.
It can be written as a sum of positive squares in 2 ways, for example, as 3528597604 + 1385402841 = 59402^2 + 37221^2 .
It is a cyclic number.
It is not a de Polignac number, because 4914000445 - 27 = 4914000317 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 491400040 + ... + 491400049.
It is an arithmetic number, because the mean of its divisors is an integer number (1474200135).
Almost surely, 24914000445 is an apocalyptic number.
It is an amenable number.
4914000445 is a deficient number, since it is larger than the sum of its proper divisors (982800095).
4914000445 is an equidigital number, since it uses as much as digits as its factorization.
4914000445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 982800094.
The product of its (nonzero) digits is 11520, while the sum is 31.
The square root of 4914000445 is about 70099.9318473278. The cubic root of 4914000445 is about 1700.1153837486.
The spelling of 4914000445 in words is "four billion, nine hundred fourteen million, four hundred forty-five", and thus it is an aban number.
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