Base | Representation |
---|---|
bin | 100011110101110110001… |
… | …1011110011010000101000 |
3 | 122102220212100121121122111 |
4 | 1013223230123303100220 |
5 | 1121201421300411130 |
6 | 14250550043132104 |
7 | 1015614565420015 |
oct | 107535433632050 |
9 | 18386770547574 |
10 | 4925999232040 |
11 | 162a117167297 |
12 | 676837214034 |
13 | 29969ab197c3 |
14 | 1305c369a70c |
15 | 8820ac8802a |
hex | 47aec6f3428 |
4925999232040 has 32 divisors (see below), whose sum is σ = 11092883220360. Its totient is φ = 1968731257600.
The previous prime is 4925999231957. The next prime is 4925999232041. The reversal of 4925999232040 is 402329995294.
It can be written as a sum of positive squares in 4 ways, for example, as 4831458971364 + 94540260676 = 2198058^2 + 307474^2 .
It is not an unprimeable number, because it can be changed into a prime (4925999232041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52090771 + ... + 52185250.
Almost surely, 24925999232040 is an apocalyptic number.
4925999232040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4925999232040 is an abundant number, since it is smaller than the sum of its proper divisors (6166883988320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4925999232040 is a wasteful number, since it uses less digits than its factorization.
4925999232040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104277213 (or 104277209 counting only the distinct ones).
The product of its (nonzero) digits is 12597120, while the sum is 58.
The spelling of 4925999232040 in words is "four trillion, nine hundred twenty-five billion, nine hundred ninety-nine million, two hundred thirty-two thousand, forty".
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