Base | Representation |
---|---|
bin | 100011110101110110001… |
… | …1011110011010001001111 |
3 | 122102220212100121121200221 |
4 | 1013223230123303101033 |
5 | 1121201421300411304 |
6 | 14250550043132211 |
7 | 1015614565420102 |
oct | 107535433632117 |
9 | 18386770547627 |
10 | 4925999232079 |
11 | 162a117167322 |
12 | 676837214067 |
13 | 29969ab19823 |
14 | 1305c369a739 |
15 | 8820ac88054 |
hex | 47aec6f344f |
4925999232079 has 2 divisors, whose sum is σ = 4925999232080. Its totient is φ = 4925999232078.
The previous prime is 4925999232041. The next prime is 4925999232103. The reversal of 4925999232079 is 9702329995294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4925999232079 - 29 = 4925999231567 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4925999231999 and 4925999232017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4925999242079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2462999616039 + 2462999616040.
It is an arithmetic number, because the mean of its divisors is an integer number (2462999616040).
Almost surely, 24925999232079 is an apocalyptic number.
4925999232079 is a deficient number, since it is larger than the sum of its proper divisors (1).
4925999232079 is an equidigital number, since it uses as much as digits as its factorization.
4925999232079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 198404640, while the sum is 70.
The spelling of 4925999232079 in words is "four trillion, nine hundred twenty-five billion, nine hundred ninety-nine million, two hundred thirty-two thousand, seventy-nine".
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