Base | Representation |
---|---|
bin | 100100001001011100001… |
… | …0011100000010110100101 |
3 | 122120221110122022022001211 |
4 | 1020102320103200112211 |
5 | 1122344104011041143 |
6 | 14322145110151421 |
7 | 1021634340626614 |
oct | 110227023402645 |
9 | 18527418268054 |
10 | 4968074315173 |
11 | 1645a48484a72 |
12 | 682a1a052571 |
13 | 2a0644a747b8 |
14 | 1326556a987b |
15 | 8936ea1449d |
hex | 484b84e05a5 |
4968074315173 has 2 divisors, whose sum is σ = 4968074315174. Its totient is φ = 4968074315172.
The previous prime is 4968074315123. The next prime is 4968074315207. The reversal of 4968074315173 is 3715134708694.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3826867112644 + 1141207202529 = 1956238^2 + 1068273^2 .
It is a cyclic number.
It is not a de Polignac number, because 4968074315173 - 29 = 4968074314661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4968074315123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2484037157586 + 2484037157587.
It is an arithmetic number, because the mean of its divisors is an integer number (2484037157587).
Almost surely, 24968074315173 is an apocalyptic number.
It is an amenable number.
4968074315173 is a deficient number, since it is larger than the sum of its proper divisors (1).
4968074315173 is an equidigital number, since it uses as much as digits as its factorization.
4968074315173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15240960, while the sum is 58.
The spelling of 4968074315173 in words is "four trillion, nine hundred sixty-eight billion, seventy-four million, three hundred fifteen thousand, one hundred seventy-three".
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