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497536999133 is a prime number
BaseRepresentation
bin1110011110101111000…
…01000001111011011101
31202120020012122022020012
413033113201001323131
531122423432433013
61020322040333005
750642300466656
oct7172741017335
91676205568205
10497536999133
11182005735499
1280514174165
1337bc0aa4305
141a11c08452d
15ce1e7b51a8
hex73d7841edd

497536999133 has 2 divisors, whose sum is σ = 497536999134. Its totient is φ = 497536999132.

The previous prime is 497536999073. The next prime is 497536999147. The reversal of 497536999133 is 331999635794.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 474827111929 + 22709887204 = 689077^2 + 150698^2 .

It is a cyclic number.

It is not a de Polignac number, because 497536999133 - 232 = 493242031837 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (497536990133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248768499566 + 248768499567.

It is an arithmetic number, because the mean of its divisors is an integer number (248768499567).

Almost surely, 2497536999133 is an apocalyptic number.

It is an amenable number.

497536999133 is a deficient number, since it is larger than the sum of its proper divisors (1).

497536999133 is an equidigital number, since it uses as much as digits as its factorization.

497536999133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 148803480, while the sum is 68.

The spelling of 497536999133 in words is "four hundred ninety-seven billion, five hundred thirty-six million, nine hundred ninety-nine thousand, one hundred thirty-three".