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49820259493 is a prime number
BaseRepresentation
bin101110011001100001…
…001101010010100101
311202121001121102000001
4232121201031102211
51304012441300433
634515341021301
73412410134644
oct563141152245
9152531542001
1049820259493
111a146268384
1297a4854831
13490c759cb4
1425a890335b
151468bdd57d
hexb9984d4a5

49820259493 has 2 divisors, whose sum is σ = 49820259494. Its totient is φ = 49820259492.

The previous prime is 49820259491. The next prime is 49820259529. The reversal of 49820259493 is 39495202894.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42093497889 + 7726761604 = 205167^2 + 87902^2 .

It is a cyclic number.

It is not a de Polignac number, because 49820259493 - 21 = 49820259491 is a prime.

Together with 49820259491, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49820259491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24910129746 + 24910129747.

It is an arithmetic number, because the mean of its divisors is an integer number (24910129747).

Almost surely, 249820259493 is an apocalyptic number.

It is an amenable number.

49820259493 is a deficient number, since it is larger than the sum of its proper divisors (1).

49820259493 is an equidigital number, since it uses as much as digits as its factorization.

49820259493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5598720, while the sum is 55.

The spelling of 49820259493 in words is "forty-nine billion, eight hundred twenty million, two hundred fifty-nine thousand, four hundred ninety-three".