Base | Representation |
---|---|
bin | 100100011001011010001… |
… | …0101010111010111101011 |
3 | 122201012222120212010211012 |
4 | 1020302310111113113223 |
5 | 1123424322030312141 |
6 | 14350020022454135 |
7 | 1024260220413554 |
oct | 110626425272753 |
9 | 18635876763735 |
10 | 5002367432171 |
11 | 165954600537a |
12 | 6895aa89434b |
13 | 2a394b6b91c5 |
14 | 134189d6932b |
15 | 8a1ca4b2ceb |
hex | 48cb45575eb |
5002367432171 has 2 divisors, whose sum is σ = 5002367432172. Its totient is φ = 5002367432170.
The previous prime is 5002367432137. The next prime is 5002367432173. The reversal of 5002367432171 is 1712347632005.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5002367432171 is a prime.
It is a Sophie Germain prime.
Together with 5002367432173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5002367432173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2501183716085 + 2501183716086.
It is an arithmetic number, because the mean of its divisors is an integer number (2501183716086).
Almost surely, 25002367432171 is an apocalyptic number.
5002367432171 is a deficient number, since it is larger than the sum of its proper divisors (1).
5002367432171 is an equidigital number, since it uses as much as digits as its factorization.
5002367432171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 5002367432171 in words is "five trillion, two billion, three hundred sixty-seven million, four hundred thirty-two thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •